The get router info ospf database brief output on FGT-2 clearly indicates that Area 0.0.0.5 is configured as a
[Stub] area.
In OSPF, a Stub Area is specifically designed to reduce the size of the Link State Database (LSDB) on internal routers. The primary behavior of a Stub area is that it does not accept Type 5 (AS External) LSAs.
* FGT-3 is the ASBR (Autonomous System Border Router) and is importing static routes, which are generated as Type 5 LSAs in the OSPF domain.
* FGT-1 acts as the ABR (Area Border Router). Because Area 0.0.0.5 is a Stub area, FGT-1 blocks these Type 5 LSAs from entering Area 0.0.0.5.
* Consequently, FGT-2 will not receive the specific external routes advertised by FGT-3. Instead, the ABR (FGT-1) injects a default route (0.0.0.0/0) into the Stub area to allow connectivity to the external world, which is visible in the database output.
While the question text mentions FGT-3 not receiving routes, the definitive configuration shown in the exhibit is the Stub area setting, which directly corresponds to the blocking of Type 5 LSA propagation (Option A).

The correct answer is D .
The exhibit shows:
* session_count=591
* clash=162
* memory_tension_drop=0
* TCP sessions:
* 166 in NONE state
* 1 in ESTABLISHED state
* 3 in SYN_SENT state
* 2 in TIME_WAIT state
The study guide explains the TCP protocol states and states explicitly:
"When a session is closed by both the sender and receiver, FortiGate keeps that session in the session table for a few seconds, to allow for any out-of-order packets that might arrive after the FIN/ACK packet. This is the state value 5." In diagnose sys session stat, the exhibit shows 2 in TIME_WAIT state . Since TIME_WAIT = state value 5
, those are the sessions being kept briefly for possible out-of-order packets. That makes D correct.
Why the other options are wrong:
* A is wrong because session_count=591 is the total number of sessions, while the TCP sessions shown add up to only 172 (166 + 1 + 3 + 2). So not all sessions in the table are TCP sessions.
* B is wrong because the study guide says the number of sessions deleted because of low free memory is shown by memory_tension_drop , and in the exhibit it is 0 , not 162.
* C is wrong because the study guide defines ephemeral/open TCP sessions as those not fully established , but the exhibit does not say all 166 in NONE state are specifically "waiting to complete the three-way handshake." The clearest directly supported statement from the displayed states is the 2 TIME_WAIT sessions retained for out-of-order packets.
So the verified answer is: D .

The correct answer is B .
The study guide states that for TCP , the protocol state is a two-digit number . The first digit is the server- side state and is 0 when the session is not subject to inspection . The second digit is the client-side state .
It also shows that value 1 = ESTABLISHED
So, for a normal TCP session with no inspection, proto_state=01 means:
* first digit 0 = no inspection
* second digit 1 = ESTABLISHED
That makes B correct.
Why the other options are wrong:
* A is wrong because for UDP , the study guide says 00 = one-way traffic and 01 = two-way traffic
* C is wrong because 10 does not represent the normal established TCP session described in the study guide. The established example shown is based on state value 1 , and the guide explicitly highlights proto_state=11 when both server-side and client-side TCP handshakes are completed
* D is wrong because for ICMP , the study guide says "the protocol state is always 00"
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The correct answer is D. The inbound IPsec SA was copied to the NPU.
The exhibit shows:
* npu_flag=02
* dec_npuid=1
* enc_npuid=0
The study guide gives the exact meaning of the npu_flag field:
* npu_flag=00 = Both IPsec SAs loaded to the kernel
* npu_flag=01 = Outbound IPsec SA copied to NPU
* npu_flag=02 = Inbound IPsec SA copied to NPU
* npu_flag=03 = Both outbound and inbound IPsec SAs copied to NPU
It also explains: "If the first IPsec packet is inbound and can be offloaded, the inbound SA is copied to the NPU and the npu_flag changes to 02. After both SAs are copied to the NPU, the npu_flag changes to
03."
So with npu_flag=02, only the inbound SA has been copied to the NPU. That makes D correct.
Why the other options are wrong:
* A is wrong because outbound-only offload would be npu_flag=01, not 02
* C is wrong because both directions offloaded would be npu_flag=03, not 02
* B is wrong because dec_npuid=1 identifies the NPU ID used for decryption, but it does not state that the processor is specifically NP6 . The study guide only maps the offload state through the npu_flag values in this context, not the NPU model from this field alone So the verified answer is: D .