Online Access Free Oracle.1z0-071.v2025-01-23.q137 Practice Test (Page 15)

1z0-071 Exam Question 66

View the Exhibit and examine the data in the PRODUCTStable.

Which statement would add a column called PRICE, which cannot contain NULL?
ALTER TABLE products

A.ADD price NUMBER(8,2) DEFAULT NOT NULL;
ALTER TABLE products

B.ADD price NUMBER(8,2) NOT NULL;
ALTER TABLE products

C.ADD price NUMBER(8,2) DEFAULT CONSTRAINT p_nn NOT NULL.

D.ADD price NUMBER(8,2) DEFAULT 0 NOT NULL;
ALTER TABLE products

1z0-071 Exam Question 67

Examine the structure and data in the PRICE_LIST table:

You plan to give a discount of 25% on the product price and need to display the discount amount in the same format as the PROD_PRICE.
Which SQL statement would give the required result?

A.SELECT TO_NUMBER (TO_NUMBER(prod_price, '$99,999.99') * . 25, '$99,999.00')FROM PRICE_LIST

B.SELECT TO_CHAR (prod_price* .25, '$99,999.99')FROM PRICE_LIST

C.SELECT TO_CHAR (TO_NUMBER(prod_price, '$99,999.99') * . 25, '$99,999.00')FROM PRICE_LIST

D.SELECT TO_CHAR (TO_NUMBER(prod_price) * .25, '$99,999.00')FROM PRICE_LIST

1z0-071 Exam Question 68

View the exhibit and examine the structure of the EMPLOYEES table.

You want to select all employees having 100 as their MANAGER_ID manages and their manager.
You want the output in two columns: the first column should have the employee's manager's LAST_NAME and the second column should have the employee's LAST_NAME.
Which SQL statement would you execute?

A.SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE m.manager_id=100;

B.SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON e.employee_id = m.manager_idWHERE m.manager_id=100;

C.SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eON m.employee_id = e.manager_idWHERE e.manager_id=100;

D.SELECT m.last_name "Manager", e.last_name "Employee"FROM employees m JOIN employees eWHERE m.employee_id = e.manager_id AND e.manager_id=100

1z0-071 Exam Question 69

Table EMPLOYEES contains columns including EMPLOYEE_ID, JOB_ID and SALARY.
Only the EMPLOYEE_ID column is indexed.
Rows exist for employees 100 and 200.
Examine this statement:

Which two statements are true? (Choose two.)

A.Employees 100 will have JOB_ID set to the same value as the JOB_ID of employee 200

B.Employee 100 will have SALARY set to the same value as the SALARY of employee 200

C.Employee 200 will have SALARY set to the same value as the SALARY of employee 100

D.Employees 100 and 200 will have the same JOB_ID as before the update command

E.Employees 100 and 200 will have the same SALARY as before the update command

F.Employee 200 will have JOB_ID set to the same value as the JOB_ID of employee 100

1z0-071 Exam Question 70

Examine the description of the EMPLOYEES table:

Which query is valid?

A.SELECT dept_id, join date, SUM(salary) FROM employees GROUP BY dept_id,join_date;

B.SELECT dept_id, MAX (AVG(salary)) FROM employees GROUP BY dept_id;

C.SELECT dept_id, AVG(NAX(salary)) FROM employees GROUP BY dept_id;

D.SELECT dept_id, join_date, SUM(salary) FROM employees GROUP BY dept_id;

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1z0-071 Exam Question 66

1z0-071 Exam Question 67

1z0-071 Exam Question 68

1z0-071 Exam Question 69

1z0-071 Exam Question 70

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