We are told that the number of people expected to audition this year is 4 times the number of people who auditioned last year.
Let:
t=number of people who auditioned last year
and
A(t)=number of people expected to audition this year
Since this year's number is 4 times last year's number, the function is:
A(t)=4t
The question says that 330 people auditioned last year, so:
t=330
Now substitute 330 into the function:
A(330)=4(330)
A(330)=1320
So, the correct function notation is:
A(330)=1,320
This means: when 330 people auditioned last year, 1,320 people are expected to audition this year.
Therefore, the correct answer is:
B

The graph is a logistic growth curve.
A logistic growth curve has two main concavity regions:
" concave up before the inflection point "
and
" concave down after the inflection point "
From the graph, the function increases faster and faster until about:
x=6
After x=6, the graph continues increasing, but it begins to flatten out. That means the number of members is increasing slower and slower.
This is concave down behavior.
Therefore, one interval where the graph is concave down is:
(6#11)
So the correct answer is:
# ( " D " )

The function w(t)gives the number of workers at the job site thours after 6:00 a.m.
We need to find the difference between:
w(4)
and
w(8)
Because w(t)represents workers, the difference will be measured in workers, not hours.
First, evaluate w(4):
w(4)=0.03(4)^4-0.81(4)^3+7.55(4)^2-26.62(4)+44
w(4)=0.03(256)-0.81(64)+7.55(16)-106.48+44
w(4)=7.68-51.84+120.8-106.48+44
w(4)=14.16
Now evaluate w(8):
w(8)=0.03(8)^4-0.81(8)^3+7.55(8)^2-26.62(8)+44
w(8)=0.03(4096)-0.81(512)+7.55(64)-212.96+44
w(8)=122.88-414.72+483.2-212.96+44
w(8)=22.4
Now find the difference:
22.4-14.16=8.24
This is approximately:
8 " workers "

The graph shows the temperature of an object changing over time.
The horizontal axis represents:
" Time in minutes "
The vertical axis represents:
" Temperature in degrees Fahrenheit "
The curve is decreasing quickly at first and then begins to level off. This is the shape of an exponential decay function.
A horizontal asymptote is a horizontal line that the graph approaches as time increases.
Because a horizontal asymptote is a horizontal line, its equation must have the form:
y= " constant "
From the graph, the temperature approaches about:
25^ # F
So the horizontal asymptote is:
y=25
This means the object's temperature gets closer and closer to 25^ # Fover time.

The graph shows the queue size changing over time.
The horizontal axis represents:
" Time in minutes "
The vertical axis represents:
" Queue size "
The graph is a decreasing exponential curve. It starts near 750people and decreases quickly at first. Then the curve begins to flatten near:
y=100
A horizontal asymptote is the horizontal line that the graph approaches as time continues.
Here, the graph approaches the horizontal line:
y=100
This means that as time passes, the number of people in the virtual queue gets closer and closer to 100.
It does not mean the queue decreases to 0, because the graph levels off near 100, not near 0.
Therefore, the correct interpretation is:
" As time passes, the number of people in the queue approaches 100. "