This question asks us to interpret a value from a graph.
The horizontal axis represents:
Days
The vertical axis represents:
Practice duration in minutes
We need to find the practice duration on day 8.
To do this:
Locate 8 on the horizontal axis.
Move vertically until you reach the blue graph.
Read the corresponding value on the vertical axis.
From the graph, when:
x=8
the blue graph is at:
y=115
So the musician practiced for:
115 minutes

The graph shows a decreasing exponential model.
The vertical axis represents:
" Licensed sellers "
The horizontal axis represents:
" Time in years "
The graph starts near 700 licensed sellers and decreases over time. However, it does not appear to decrease all the way to 0. Instead, it levels off near:
y=100
That horizontal line is the horizontal asymptote.
A horizontal asymptote represents the long-term value the function approaches as time continues.
So the correct interpretation is:
" In the long run, the number of licensed sellers nears 100. "
Therefore, the correct answer is:
# ( " C " )

From week 1 to week 7, the graph is increasing and becoming steeper.
In Applied Algebra, when a graph is increasing and its slope is getting larger, the quantity is said to be:
" increasing faster and faster "
This interval is on the early increasing part of the logistic curve, before the graph begins to level off.
Therefore, the correct answer is:
# ( " B " )

From t=6.2to about t=8.5, the graph is increasing, but it is becoming less steep as it approaches a local maximum.
That means the number of customers is:
" increasing slower and slower "
After the local maximum, from about t=8.5to t=10.1, the graph begins to decrease and becomes steeper downward.
That means the number of customers is:
" decreasing faster and faster "
So the full description is:
" The number of customers increases slower and slower and then decreases faster and faster. " Therefore, the correct answer is:
# ( " D " )

We need to compare the two account values after:
t=3
First, find the value of Account 1:
A_1 (3)=6,500× # 1.05 # ^3
A_1 (3)=6,500×1.157625
A_1 (3)#7,524.56
Now find the value of Account 2:
A_2 (3)=3,000× # 0.96 # ^3
A_2 (3)=3,000×0.884736
A_2 (3)#2,654.21
Now subtract:
7,524.56-2,654.21=4,870.35
So Account 1 is about:
$4,870
greater than Account 2 after 3 years.
Therefore, the correct answer is:
# ( " C " )