The function f(n) gives the distance traveled by vehicle B.
The input n represents the distance traveled by vehicle A.
The problem says vehicle B travels 17 more than vehicle A. The phrase "17 more than" means we add 17 to the amount traveled by vehicle A.
So the relationship is:
f(n)=n+17
For example, if vehicle A traveled 50 miles, then vehicle B traveled:
f(50)=50+17=67
So the correct function is:
f(n)=n+17
Therefore, the correct answer is:
B

The graph represents:
p(t)= " number of active players "
where:
t= " hours after 11:00 a.m. "
The phrase "decreasing faster and faster" means two things are happening:
The graph is going downward, so the number of players is decreasing.
The graph is becoming steeper downward, so the rate of decrease is increasing.
This corresponds to a graph that is decreasing and concave down.
Looking at the graph, the number of active players reaches a maximum around:
t#9
After that, the graph begins decreasing. Near the far right side of the graph, especially around:
t=11.2 " to " t=11.5
the curve is dropping more and more steeply.
That means the number of players is decreasing faster and faster on that interval.

A horizontal asymptote is a horizontal line that a graph approaches as the input increases. Horizontal lines always have equations in the form y=constant, not x=constant. In this graph, the number of client accounts decreases over time and levels off near 125 accounts. Since the graph approaches 125 on the vertical axis, the horizontal asymptote is y=125. Choices x=125 and x=550 are vertical lines, so they cannot represent horizontal asymptotes. Choice y=550 represents a higher value near the beginning of the graph, not the long- term level. Therefore, the correct equation of the horizontal asymptote is y=125, making the answer B.

The scatterplot shows data collected over time, and a regression curve is used to model the pattern.
Extrapolation means using a model to make predictions slightly outside the observed data range. In Applied Algebra, extrapolation can be appropriate when:
" the regression model fits the data reasonably well "
and the predicted x-values are not too far outside the observed data.
From the scatterplot, the data points appear to run approximately from:
x=3 " to " x=15
So the observed data range is about:
15-3=12
A reasonable extrapolation range extends a little beyond the data, but not too far. The interval:
x=0 " to " x=18
extends about 3 units beyond each side of the observed data, which is reasonable.
The interval:
x=-3 " to " x=21
extends much farther beyond the data and would be less reliable.
Also, r^2does not have to equal exactly 1 for extrapolation to be useful. A value less than 1 can still represent a strong model.
Therefore, the correct answer is:
# ( " A " )

The graph represents the value of an investment account over time. The horizontal axis gives time in years, and the vertical axis gives the total account value in dollars. To find the value after 4 years, locate x=4 on the horizontal axis and read the corresponding G(x)-value on the graph. The plotted exponential growth curve is slightly above $1,000 at 4 years, closest to $1,052.87. Because the graph shows an increasing exponential trend, values such as $480.52, $584.62, and $711.28 are too low for the account value at x=4. The correct interpretation is that after 4 years, the investment account is worth approximately $1,052.87. Therefore, the correct answer is D.