The graph shows a logistic regression model for rabbit population data.
The given value is:
r^2=0.94
An r^2value close to 1means the model fits the data well. Since 0.94is close to 1, the regression model is a strong fit.
However, extrapolation should still be done carefully. Extrapolation means using the model to predict values outside the observed data range.
From the scatterplot, the data values appear to run roughly from about:
x=4 " to " x=20
A reasonable extrapolation range should stay close to the observed data. The interval:
x=0 " to " x=24
extends slightly beyond the data on both sides, so it is more reasonable than the much wider interval:
x=-4 " to " x=28
The statements saying extrapolation is not appropriate because r^2 < 1or because r^2 > 0.7are not valid interpretations.

The table gives the percent of customers with fiber internet for each year since 2020.
Since 2023 is:
2023#2020=3
we use the row where:
Years since 2020=3
From the table, the percent of customers with fiber internet in 2023 is:
57%
The company has approximately:
1,050
customers each year.
Now find 57% of 1,050:
0.57×1,050=598.5
The closest answer choice is:
598
So approximately 598 customers had fiber internet in 2023.
Therefore, the correct answer is:
C

We are told that the number of people expected to audition this year is 4 times the number of people who auditioned last year.
Let:
t=number of people who auditioned last year
and
A(t)=number of people expected to audition this year
Since this year's number is 4 times last year's number, the function is:
A(t)=4t
The question says that 330 people auditioned last year, so:
t=330
Now substitute 330 into the function:
A(330)=4(330)
A(330)=1320
So, the correct function notation is:
A(330)=1,320
This means: when 330 people auditioned last year, 1,320 people are expected to audition this year.
Therefore, the correct answer is:
B

The graph shows:
P(t)= " weekly profit in thousands of dollars "
where:
t= " years since opening "
The graph is a downward-opening curve, so it has a maximum value at its highest point. In Applied Algebra, the highest point of this kind of polynomial graph is called the vertex.
To answer the question, we need the t-value of the vertex because the question asks when the store had its maximum weekly profit.
From the graph, the highest point occurs between:
t=5
and
t=6
More specifically, it is approximately:
t=5.5
So the store had its maximum weekly profit approximately:
5.5 " years after opening "

The graph compares the spread of two viruses over time.
The horizontal axis represents:
t= " time in months "
The vertical axis represents:
" percentage of the population affected "
The graph shows:
Virus A as the solid blue curve.
Virus B as the dashed blue curve.
To determine which statement is correct, we compare when each virus reaches the same population percentage.
At 20%:
Virus B reaches 20%earlier, around t#5months.
Virus A reaches 20%later, around t#6.5months.
So Virus B affects 20%of the population before Virus A does.
For higher percentages such as 60%, 70%, and 80%, Virus A rises more quickly after about 50%, so Virus A reaches those percentages before Virus B.
Therefore, the correct conclusion is:
" Virus B affects " 20% " of the population before virus A does. "